Question

If m, n are the roots of the equation x - 6x + 3 = 0,
then the equation whose roots are m2, n2 could be:​

Answer 1

Answer:

m+n = -b/a = -(-6/1) = 6

m.n = c/a = 3/1 = 3

m^2 + n^2 = (m+n)^2 - 2mn = 36 - 6 = 30

m^2.n^2 = 9

Eqn whose roots are m^2 and n^2 is

x^2 - (m^2 + n^2)x + m^2.n^2 =

x^2 -30x +9 = 0