If m ,n are the zeroes of ax2-bx+c.find the value of a and c .if m+n/mn =10
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Answer:
(mn)(ba)2=(1+mn)2(ca)
Explanation:
ax2+bx+c=0→p(x)=x2+(ba)x+(ca)=0
Let x1,x2 be the the roots of p(x)=0
then
p(x)=(x+x1)(x+x2)=x2+(x1+x2)x+x1x2
but x1x2=mn then
p(x)=x2+(1+mn)x1x+(mn)x21 Now after comparison we have
{(1+mn)x1=ba(mn)x21=ca
or
(ba)2(1+mn)2=(ca)(mn) or
(mn)(ba)2=(1+mn)2(ca)
(mn)(ba)2=(1+mn)2(ca)
Explanation:
ax2+bx+c=0→p(x)=x2+(ba)x+(ca)=0
Let x1,x2 be the the roots of p(x)=0
then
p(x)=(x+x1)(x+x2)=x2+(x1+x2)x+x1x2
but x1x2=mn then
p(x)=x2+(1+mn)x1x+(mn)x21 Now after comparison we have
{(1+mn)x1=ba(mn)x21=ca
or
(ba)2(1+mn)2=(ca)(mn) or
(mn)(ba)2=(1+mn)2(ca)
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