If m,n are the zeros of the polynomial bx2+ax+c, then the value of m2+n2 is what.....? Pls answer fast it is really important pls pls
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Concept used :-
The sum of the roots of the Equation ax² + bx + c = 0 , is given by = (-b/a)
and ,
→ Product of roots of the Equation is given by = c/a.
Solution :-
Given Polynomial = bx² + ax + c
where,
→ a = b
→ b = a
→ c = c
So,
→ sum of zeros = (m + n) = (-b/a) = (-a/b) ----- Eqn.(1)
→ Product of zeros = m * n = c/a = (c/b) ------ Eqn.(2)
now, using a² + b² = (a + b)² - 2ab we get,
→ m² + n² = (m + n)² - 2mn
→ m² + n² = (-a/b)² - 2(c/b)
→ m² + n² = a²/b² - 2c/b
→ m² + n² = (a² - 2bc) / (b²) (Ans.)
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