Question

If m:n is the duplicate ratio of m+x:n+x show that x^2 =mn

Answer 1

m:n =(m+x)^2:(n+x)^2
m/n=(m+x)^2/[n+x]^2
m[n+x]^2 =[m+x]^2*n
x^2[n-m]=x[2mn-2nm] +m^2*n-n^2*m
x^2[m-n] =mn(m-n)
x^2=mn//