Math, asked by poreddykavitha86, 10 months ago

if m,n,k are rational and m=k+n/k then the roots of x2+MX+n are


Answers

Answered by 10522014
10

Step-by-step explanation:

x+mx+n=0

x2+(k+nk)x+n=0

x=−(k+nk)±(k+nk)2−4n−−−−−−−−−−−−√2

x=−(k+nk)±k2+n2k2+2n−4n−−−−−−−−−−−−−−−√2

x=−(k+nk)±(k−nk)2

x=−k,−nk.

Answered by bseetharam60
6

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