if m,n,k are rational and m=k+n/k then the roots of x2+MX+n are
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Step-by-step explanation:
x+mx+n=0
x2+(k+nk)x+n=0
x=−(k+nk)±(k+nk)2−4n−−−−−−−−−−−−√2
x=−(k+nk)±k2+n2k2+2n−4n−−−−−−−−−−−−−−−√2
x=−(k+nk)±(k−nk)2
x=−k,−nk.
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