Math, asked by sakhipraveen27, 1 year ago

If m+n÷m+3n=2÷3 find 2n^2÷3m^2 +mn

Answers

Answered by Anonymous
29

 \frac{m + n}{m + 3n}  =  \frac{2}{3}
3m + 3n = 2m + 6n
m = 3n
 \frac{n}{m}  =  \frac{1}{3}
 \frac{ {n}^{2} }{ {m}^{2} }  =  \frac{1}{9}
 \frac{2 {n}^{2} }{3 {n}^{2} }  =  \frac{2}{27}

sakhipraveen27: No
Anonymous: sorry. but how can i edit the answer
sakhipraveen27: I will help u later.now I'm busy
sakhipraveen27: M+n/m+3n=3/3
sakhipraveen27: 3n+3n=2m+6m
sakhipraveen27: M=3n
sakhipraveen27: M/n=3
sakhipraveen27: 2n^2/3m+mn= 2/3*m/n)^2 !*3/1) = 2 /27 +3 = 2/30 =1/15
Answered by Gauri6743494
19

Answer:1/15

Step-by-step explanation:

m+n/m+3n =2/3

Cross multiply

3m+3n=2m+6n

m=3n

m/n=3/1

Or

m:n=3:1

Take m=3k

n=k

2n^2 ÷ 3m^2 + mn

Now substitute the value of m and n in the given equation :

As done in the picture attached

Attachments:
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