if √m +√n -√p =0 find (m+n-p)^2
Answers
Before starting this let me tell you just two formulas.
1. (a+b)^2= a^2+2ab+b^2.
And
2. (a+b+c)^2= a^2+b^2+c^2+2ab+2bc+2ca.
Now as you have learnt the two formulas, the problem can be solved so easily.
See that the 2nd formula is going to work properly here.
According to the 2nd formula we have got,
a = root (m)
b = root (n)
c = -root (p) [Don't avoid the -ve sign!]
Now squaring both sides we obtain,
m+n+p+2root (m×n) -2root (n×p) -2root (m×p)=0
Similarly,
m+n+p = 2root (np)+2root (mp)-2root (mn)
Put -p in place of p, you will get...
m+n-p = - [2root(np)+2root(mp)+2root(mn)]
Last step is just squaring both side again. And you get the answer.
(m+n-p)^2= 4np+4mn+4mp+4p root(mn)
+4m root(np) +4n root(mp)
And finally the headache is gone!!!
Hope that you will try to read till the end by keeping the pace and understand the matter what I did actually.
Yes the first formula was of nothing use but the second formula helped us a lot to complete the journey.
If you like the explanation then please hit the brainliest button...
Also hit the button since I applied efforts to type so long in my android mobile actually...