If √m+√n-√p=0, find the value of (m+n-p)^2
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Given, root m + root n = root p
On squaring both sides, we get
= m + n + 2 root mn = p
= m +n - p = - 2 root mn
on squaring both sides, we get
= (m+n-p)^2 = 4 mn.
Hope this helps!
On squaring both sides, we get
= m + n + 2 root mn = p
= m +n - p = - 2 root mn
on squaring both sides, we get
= (m+n-p)^2 = 4 mn.
Hope this helps!
devanshlodhamaowf2z6:
How did u gat 2rootmn
Hey
(m+n)^2 = m^2+ n^2 + 2mn. it is (a+b)^2 formula.
Ok
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