Question

if m+n+p=9 and m2+n2+p2=41,find the value of (mn+np+pm).​

Answer 1

⭐Solution⭐

✏Given here

m+n+p = 9...(1)

m²+n²+p²= 41.....(2)

✏Find here

(mn+np+pm) = ❓

Now,

we know

(x+y+z)²= (x2+y²+z²+)+2(xy+yz+zx)

like thats ,

(m+n+p)²= (m²+n²+p²)+2(mn+np+pm)

keep value by (1) and (2)

(9)²= (41)+2(mn+np+pm)

=>2(mn+np+pm)= 81 - 41

=>(mn+np+pm) = 40/2

=>(mn+np+pm)= 20

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Answer 2

Answer:

-20

Step-by-step explanation:

m^2 + n^2 + p^2= 41

or, ( m + n + p)^2 + 2(mn + pn + pm)= 41

or, ( 9)^2 + 2( mn + pn + pm) = 41

or, 81 + 2( mn + pn + pm) = 41

or, ( mn + pn + pm) = -20