If m, n, p are natural numbers such
that (m2 + n2
) = p2
, then (m, n, p) is
called
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13
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Answered by
3
(m^2+n^2)=p^2
m,n,P are natural no.
let m=1,2,3....so on
m^2+n^2=p^2
m=1then
1×1+n^2=p^2
1+n^2=p^2
n^2= -1+p^2
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