Question

if m=(prime integer between 1and 11)find MuN ,MnN?​

Answer 1

Answer:

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Step-by-step explanation:

Let I=7n+7m, then we observe that 71,72,73 and 74ends in 7,9,3 and 1 respectively.

Thus, 71 ends in 7, 9, 3 or 1 according as i is of the form 4k + 1, 4k + 2, 4k - 1 and 4k respectively.

If S is the sample space, then n(S)=(100)2

7m+7n is divisible by 5, if

(i) m is of the form 4k + 1 and n is of the form 4k - 1 or

(ii) m is of the form 4k + 2 and n is of the form 4k or

(iii) m is of the form 4k - 1 and n is of the form 4k + 1 or

(iv) m is of the form 4k and n is of the form 4k + 2 or

So, number of favourable ordered pairs (m,n)=4×25×25

∴ Required probability =(100)24×25×25=41.

Hence, option A is correct.