if m=x+1/x-1 and n=x-1/x+1,find m^2+n^2-mn
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Answered by
3
Given:
m²= (x+1/x-1)²
=x²+1/x²+1
=1.------›(i)
n²= (x-1/x+1)²
n²= x²+1/x²+1
n²=1.------›(ii)
mn= (x+1/x-1)(x-1/x+1)
=x²-1/x²-1
=1 ------›(iii)
substitute (i),(ii) & (iii) in m²+n²-mn
therefore we get
=1+1-1
=1
Thank you!!☺️
❄️ALL THE BEST.❄️
m²= (x+1/x-1)²
=x²+1/x²+1
=1.------›(i)
n²= (x-1/x+1)²
n²= x²+1/x²+1
n²=1.------›(ii)
mn= (x+1/x-1)(x-1/x+1)
=x²-1/x²-1
=1 ------›(iii)
substitute (i),(ii) & (iii) in m²+n²-mn
therefore we get
=1+1-1
=1
Thank you!!☺️
❄️ALL THE BEST.❄️
sagar377:
Thank you Akshay for answering but it is a different answer.
ok thanks
my answer is correct or not?
not
sorry
it's ok
thank you
Answered by
0
Step-by-step explanation:
=x+1÷x−1
n = x - 1 \div x + 1n=x−1÷x+1
m²= (x+1/x-1)²
=x²+1/x²+1
=1.------›(i)
n²= (x-1/x+1)²
n²= x²+1/x²+1
n²=1.------›(ii)
mn= (x+1/x-1)(x-1/x+1)
=x²-1/x²-1
=1 ------›(iii)
substitute (i),(ii) & (iii) in m²+n²-mn
therefore we get
=1+1-1
=1
Thank you!!☺️
❄️ALL THE BEST.❄️
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