if m=x+1/x and n=x , then m²-n²=?
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Answer:
m = x + 1 \div x - 1m=x+1÷x−1
n = x - 1 \div x + 1n=x−1÷x+1
m²= (x+1/x-1)²
=x²+1/x²+1
=1.------›(i)
n²= (x-1/x+1)²
n²= x²+1/x²+1
n²=1.------›(ii)
mn= (x+1/x-1)(x-1/x+1)
=x²-1/x²-1
=1 ------›(iii)
substitute (i),(ii) & (iii) in m²+n²-mn
therefore we get
=1+1-1
=1
Thank you!!☺️
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