If m1=10kg,m2=4kg,m3=2kg and surface is smooth the acceleration of system is
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Answer:
5g/8 is ur answer
Given,
Force on block m
1
, F
1
=m
1
g=10gN
Force on block m
1
, F
2
=m
2
gsin30
o
=4g×0.5=2gN
Force on block m
3
, F
3
=m
3
g=2gN
F
net
=F
1
+F
2
−F
3
⇒(m
1
+m
2
+m
3
)a=10g+2g−2g
⇒a=
10+4+2
10g
=
8
5g
ms
−2
Acceleration of system
8
5g
ms
−2
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