If m1 = 5kg and m₂ = 5kg, then find • (A) Acceleration of the blocks (B) Tension in the string Ginen AB = 4 m, BC = 5m, AC = 3m
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The angles B and C come out to be 37° and 53° respectively. Then apply the pulling force method. Take the 2 blocks and the string as one system. Apply forces along the string. m2 is pulled down the incline by m2gsin53°. m1 similarly in the opposite direcrion by m1gsin37°. All other forces are perpendicular to the string. The net pulling force along the string in the direction of m2 is 5gsin53° - 5gsin37°. This should equal total mass times acceleration along the string. That is 10a. Therefore a = 4g - 3g / 10 = g/10.
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