Question

If m1 and m2 are the masses constituting the rigid body, bound by some

internal forces so that the distance between the masses remain constant

then

I) Define centre of mass.

II) Derive expression for position vector of centre of mass.​

Answer 1

Answer

The forces of attraction between the particles are the internal forces. Therefore, the center of mass of the system will have no acceleration. The particles move, but the center of mass will continue to be at the same place. At the time of collision, the two particles are at one place and the center of mass will also be at that place. As the center of mass does not move, the collision will take place at the center of mass. Distance of center of mass form M

2=R− M 1 +M M 2 R = M 1 +M 2M 1 R

Ratio of the distances= M 1M 2

Answer 2

Answer: A position relative to an object or set of objects is known as the centre of mass.

Explanation:

|)Centre of mass- A position relative to an object or set of objects is known as the centre of mass. It is the system's average location, weighted by the mass of each component. The centre of mass is situated at the centroid for straightforward stiff objects with homogeneous density.

II) If a system consists of n particles of masses m1, m2, m3 ........ mn, whose positions vectors are

$r_{1} , r_{2} , r_{3} ...............r_{n}$

respectively then the position vector of the centre of mass.

r = $m_{1} r_{1} +m_{2} r_{2} +m_{3} r_{3}.........+m_{n} r_{n} / m_{1}+ m_{2}+ m_{3}......+m_{n}$

If two masses are equal i.e., m1 = m2, then the position vector of the centre of mass

$r = r_{1} +r_{2} / 2$

To know more about the centre of mass from the given link

https://brainly.in/question/19616311

https://brainly.in/question/21800956

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