Question

If m1 is the slope of line joining the points (-2,-1). (3,-2) and m2 is the slope of points (3,-1), (4, -6), find m1: m2:​

Answer 1

Answer:

1:1

Step-by-step explanation:

m1 = (y2-y1)/(x2-x1)

    = (-2+1)/(3+2)

    = -1/5

m2= (4-3)/(-6+1)

    = 1/-5

m1:m2 = -1/5 : -1/5

            = 1:1

Answer 2

Step-by-step explanation:

Let,

A(-2,-1) , B(3,-2) and

C(3,-1) , (4,-6) are the points

As we know,

$\boxed{slope(m) = \dfrac{y2-y1}{x2-x1}}$

Now,

Slope of AB (m1)

$= \dfrac{-2+1}{3+2}$

$= \dfrac{-1}{5}$

Slope of CD (m2)

$= \dfrac{-6+1}{4-3}$

$= \dfrac{-5}{1}$

Now,

$m1 : m2 = \dfrac{-1}{5} : -5$

m1 : m2 = 1 : 25