Question

If m2 – 5m + 1 = 0 and m≠0, find (i) m + 1 ?​

Answer 1

Answer:

For , the given equation (4+m)x² + (m+1)x+1=0;

a=4+m, b= m+1 and c=1.

Since , the roots are equal

Therefore,

b² - 4ac = 0

=> (m+1)² -4(4+m)×1=0

=>m²+2m+1-16-4m=0

=>m²-2m-15=0

ON SOLVING , WE GET,

m=5 , m=-3.

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Answer 2

Step-by-step explanation:

m² −5m+1=0

m²+1=5m

$m + \frac{1}{m} = 5$

Cubing on both sides