Question

if m3>m2>m1 , find the net force of m1 , m2 and m3 ( consider the surface is frictionless ) ​

Answer 1

Answer:

Correct option is

C

1+4m1(m21+m31)g

Let tension in string attached to m1 be T1, and that in the other be T2. Let the acceleration of block of mass m1$ be A, and the relative acceleration of the other two blocks be ar.

From the freebody diagram of the blocks,

m1:T1=m1A

and m2:T2−m2g=m2(ar−A)

and m3:m3g−T2=m3(ar+A)

Also the forces on the suspended pulley must balance each other. Hence

2T2=T1

Solving the above equations gives:

A=1+4m