if magnification m < 0, is the image formed errect or inverted?
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According to new Cartesian sign convention, size of height of real and inverted image is considered negative and that of virtual and erect image is considered positive.
The heigh of the object, being erect is considered positive always.
So, for positive magnification, the ratio, mentioned above, will be positive. This implies that the image height will also be positive.
The image will be virtual and erect.
If the magnification is positive, the image is upright compared to the object; if m is negative, the image is inverted compared to the object. If the magnification is less than 1 then t
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