if magnitude of A*B is equal to the root of 3 vector A dot B find the Sum of the magnitude of A plus B
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|AXB|= root 3 A.B
AB sin x=√3 x ABcosx
tan x=√3
x=60
now |A+B|2=A2+B2+2AB cos60
|A+B|=√(A2+B2+AB)
hope this helps ...if u still have doubt ask me again
AB sin x=√3 x ABcosx
tan x=√3
x=60
now |A+B|2=A2+B2+2AB cos60
|A+B|=√(A2+B2+AB)
hope this helps ...if u still have doubt ask me again
kanchansharma:
thanks alot
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