Question

If magnitude of A cross B = magnitude of A dot B, then the angle between A vector and B vector will be
1) 30 degree
2)45 degree
3)60 degree
4)75 degree​

Answer 1

Answer:

45 degrees

Explanation:

Answer 2

Answer:

Option (2) 45 degree is the angle between A vector and B vector.

Explanation:

Given, magnitude of A cross B = magnitude of A dot B.

And this can be written as,

|A× B| = |A . B|

|A||B| sin$\theta$ = |A||B| cos$\theta$

sin$\theta$ = $cos\theta$

$\frac{sin\theta}{cos\theta}$ = 1 ⇒ tan$\theta$ = tan45 °    [where tan45 ° = 1 ]

$\theta = 45$

Hence, the angle between A vector and B vector will be 45 °

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