if magnitude of vector A× vector B =√3 vector a dot vector b , then the value of Magnitude a vector . b vector is
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Answer:
The value of angle between A and B is 60° or π/3 rad
Explanation:
Given that,
A×B = √3 A·B
We know that,
A·B = ABcosФ
A×B = ABsinФ
Putting these values in we get,
A×B = √3 A·B
ABsinФ = √3 ABcosФ
sinФ / cosФ = √3
tanФ = √3
Ф = 60° or π/3 rad
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