if magnitude of vector is equals to 4 and magnitude of vector b is equals to 3 and theta is equals to 60 degree in the figure find (A) vector a dot vector b (B) magnitude of vector a cross vector b
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Answer:
The answer for a.b is 6 and AxB is 6√3
Explanation:
By using the dot rule method for a.b
We get the answer
a.b=abcostheta
Theta is given 60 so,
A.B=ABcos60
And A =4 and B=3
A.B=4*3 *1/2 ;cos60=1/2
A.B=6
By using the cross product rule for AxB we get
AxB=ABsintheta
Substituting the values we get
AxB=4*3*√3/2 we know that sin60=√3/2
AxB = 6√3
Hope it will help you..
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