Physics, asked by Rimmi1234, 9 months ago

if magnitude of vector is equals to 4 and magnitude of vector b is equals to 3 and theta is equals to 60 degree in the figure find (A) vector a dot vector b (B) magnitude of vector a cross vector b

Answers

Answered by kausalyap27
27

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OPTION A

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Answered by Tejas350
3

Answer:

The answer for a.b is 6 and AxB is 6√3

Explanation:

By using the dot rule method for a.b

We get the answer

a.b=abcostheta

Theta is given 60 so,

A.B=ABcos60

And A =4 and B=3

A.B=4*3 *1/2 ;cos60=1/2

A.B=6

By using the cross product rule for AxB we get

AxB=ABsintheta

Substituting the values we get

AxB=4*3*√3/2 we know that sin60=√3/2

AxB = 6√3

Hope it will help you..

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