If magnitude of vector produvt and scalar is equal find the angle betwween them
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⑴ When that is the case,the angle between them is 45°
⑵Reason :
Let x= Scalar product of A and B=abcosθ
y=Magnitude of Vector product of A and B=absinθ
,where θ is the smaller angle between A and B
⑶ When x=y,
absinθ =abcosθ
sinθ =cosθ
sinθ/cosθ=1
tanθ=1
θ=45° or θ=225° , 0°≤ θ≤360°
⑷ But the angle between two vectors A and B is defined as the smaller angle between them=45°
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Hope it will help u...........
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