if magnitudes of 2 vectors are 3 nd 4 nd their scalar product is 6,then find angle between 2 vectors
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Answer:
A=3,B=4A=B6
cos theta(barA.barB)/(AB)
cosθ=
→
A
.
→
B
AB
=
6
3×4
=
1
2
थीटा=60∘
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