If male and female students of section B in DPS and DAV are in ratio 3 : 2 and 4:3 respectively then male students of section B are how much percent more than female students of section B considering both the schools (approx). (A) 50% (C) 36% (B) 25% (D) 40%
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Answers
Answer:
Answer is 40
Step-by-step explanation:
I have attached an image of the answer, Hope it helps you (please cope up with the hand-writing)
Given : Male and female students of section B in DPS and DAV are in ratio 3 : 2 and 4:3 respectively
To Find : male students of section B are how much percent more than female students of section B considering both the schools (approx).
(A) 50% (C) 36% (B) 25% (D) 40%
Solution:
Data is insufficient to solve :
Assuming Both Section B have Equal students then it can be solved
Assume in each School in B section students are 35 x
Male students in B section of DPS = (3/5) * 35x = 21x
Female students in B section of DPS = (2/5) * 35x =14x
Male students in B section of DAV = (4/7) * 35x = 20x
Female students in B section of DAV = (3/7) * 35x =15x
Total male students = 21x + 20x = 41x
Total females = 14x + 15x = 29x
Males students more than female students = 41x - 29x = 12x
in Percentage = (12x/29x) * 100 = 41.37
In the given option Approximate choice is 40 %
option D ) is correct
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