Question

If
man walks 6 km to east and
8km to North, then distance from
the away to the orgin is-​

Answer 1

Answer:

Let the east direction to be

i

^

and north direction be

j

^

.

Thus displacement of the man

S

=8

i

^

+6

j

^

So, magnitude of displacement ∣

S

∣=

6

2

+8

2

=

100

=10 m

Answer 2

Answer:

walking east = 6km

walking north = 8km

distance = total length travelled

= 6 + 8

= 14km