If Manohar pays an interest of Rs 750 for 2 years on a sum of rs 4500, then the rate of interest is -
Answers
Answer:
Given,
Total interest paid, SI = 750 Rupees
The time for which Manohar pays interest is, t = 2 Years
Principal Amount, P = 4500 Rupees
Consider,
The rate of interest be r %
We know that,
Interest, SI = (P × r × t) / 100
Therefore, Rate of Interest , r = (SI × 100) / (P × t)
Now, putting the value in the above equation, we get,
Rate of Interest, r = (750 × 100) / (4500 × 2)
⇒ r = 75000/9000 = 75/9
⇒ r = 8.333 %
Therefore, Manohar pays the interest with a rate of interest of 8.333 % or 25 / 3 %.
Step-by-step explanation:
To solve this question, we already know the formula for Simple Interest (SI). It is given by,
Interest, SI = (P × r × t) / 100
Where,
P is the Principal amount.
r is the rate of interest.
t is the time.
To find the rate of interest directly, we transform the formula by simple equation transformation.
Therefore, Rate of Interest , r = (SI × 100) / (P × t)
This is the required formula to solve this question, we put all the given values and determine our answer.