Question

If mas of a cube of iron is 210g and one side of cube is 3cm. find the density of iron
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Answer 1

Explanation:

mass = 210g

one side=3cm

then volume =3^3=27cm^3

now

density=mass/volume

=210/27=7.7g/cm^3

hope it helps u.....!!!!!!

Answer 2

Answer:

The density of the iron cube is $\rho=7.77gm/cm^3$

Explanation:

Given data is,

Mass of iron cube is $m=210gm$ and

The side of the cube is $a=3cm$

Therefore,the volume of the cube is $V=a^{3}=3^3=27cm^3$

We know that density of an object is the ratio of its mass and its volume.Hence it is mathematically written as

$\rho=\frac{m}{v}$

Substituting the given values in above relation we get

$\rho=\frac{210gm}{27cm^3}=7.77gm/cm^3$

Therefore,

The density of the iron cube is $\rho=7.77gm/cm^3$

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