Chemistry, asked by Bhuii, 11 months ago

if mass of a coin is 10g then no. of moles in 10^23 g coin is

Answers

Answered by nameetjain86
0

Mass of 1 mole of coin is 10 gm

Therefore no of moles in 1gm is .1 mol therefore

Moles present is 10^23 gm is 10^23x.1= 10^22 moles

Hope it helps

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