If Mass of a planet is eight times the mass of The earth and its radius is Twice the radius of the earth,what will be the escope velocity for that planet? {Answer:—22.4km/s}
Answers
Answer:
Hello ,Good night friend
Explanation:
Given information :
Mass of Earth = M₁
Mass of the planet = eight times M₁
= 8 × M₁
= 8 M₁
Radius of Earth = R₁
Radius of the planet = two times R₁
= 2 × R₁
= 2 R₁
Escape velocity of the planet
We know that :
escape velocity = V = √ ( GM / R )
= √ ( G × 8 M₁ / 2 R₁ )
= √ ( 8 G M₁ / 2 R₁ )
= √ ( 4 G M₁ / R₁ )
= 2 √ GM₁ / R₁
= 2 × escape velocity of Earth.
We know that the escape velocity of Earth is 11.2 approx.
So : escape velocity of the planet = 2 × 11.2 km / s
= 22.4 km/s approx.
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Answer:
hey buddy ...
plzz refer to the attachment..
hope it helps...
