Physics, asked by sravyagiduturi10, 1 day ago

If mass of an object is 100 KG velocity is equal to 20 m/s calculate the kinetic energy



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Answers

Answered by Anonymous
49

Given :

  • Mass = 100 kg
  • Velocity = 20 m/s

 \\ \\

To Find :

  • Kinetic Energy

 \\ \qquad{\rule{200pt}{2pt}}

SolutioN :

 \dag Formula Used :

  •  {\underline{\boxed{\pmb{\sf{ K.E = \dfrac{1}{2} m{v}^{2} }}}}}

Where :

  • K.E = Kinetic Energy
  • m = Mass
  • v = Velocity

 \\ \\

 \dag Calculating the Kinetic Energy :

 \begin{gathered} \qquad \; \dashrightarrow \; \; \sf { K.E = \dfrac{1}{2} m{v}^{2} } \\ \\ \\ \\ \end{gathered}

 \begin{gathered} \qquad \; \dashrightarrow \; \; \sf { K.E = \dfrac{1}{2} \times 100 \times {20}^{2} } \\ \\ \\ \\ \end{gathered}

 \begin{gathered} \qquad \; \dashrightarrow \; \; \sf { K.E = \dfrac{1}{2} \times 100 \times 400 } \\ \\ \\ \\ \end{gathered}

 \begin{gathered} \qquad \; \dashrightarrow \; \; \sf { K.E = \dfrac{100}{2} \times 400 } \\ \\ \\ \\ \end{gathered}

 \begin{gathered} \qquad \; \dashrightarrow \; \; \sf { K.E = \cancel\dfrac{100}{2} \times 400 } \\ \\ \\ \\ \end{gathered}

 \begin{gathered} \qquad \; \dashrightarrow \; \; \sf { K.E = 50 \times 400 } \\ \\ \\ \\ \end{gathered}

 \begin{gathered} \qquad \; \dashrightarrow \; \; {\underline{\boxed{\pmb{\sf { Kinetic \; Energy = 20000 \; J }}}}} \; {\red{\pmb{\bigstar}}} \\ \\ \\ \\ \end{gathered}

 \\ \\

 \therefore \; The Kinetic Energy is 20000 Joules .

 \\ \qquad{\rule{200pt}{2pt}}

Answered by TheAestheticBoy
30

Question :-

  • If mass of an object is 100 kg . If the velocity is equal to 20 m/s , then calculate the Kinetic Energy .

Answer :-

  • Kinetic Energy is 20000 Joules .

 \rule {180pt}{2pt}

Given :-

  • Mass = 100 kg
  • Velocity = 20 m/s

To Find :-

  • Kinetic Energy = ?

Solution :-

As per the provided information in the given question, it is given that the Mass of object is 100 kg . Velocity of that object is 20 m/s . And, we have been ask, to calculate the Kinetic Energy .

For calculating the Kinetic Energy , the formula required :-

  •  \bf{K.E \:  =  \: \frac{1}{2} \:  {mv}^{2} } \\

Where ,

  • K.E denotes to Kinetic Energy
  • M denotes to Mass
  • V denotes to Velocity

By substituting the values :-

 \dag \:  \:  \bf{K.E \:  =  \:  \frac{1}{2}   \: \times  \: m \: \times \:{v}^{2} } \\

 \Longrightarrow \:  \:  \sf{ K.E \:  =  \:  \frac{1}{2} \:  \times \:  100 \:  \times  \: 20 }^{2}  \\

 \Longrightarrow \:  \:  \sf{K.E \:  =  \:  \frac{1}{2}  \:  \times  \: 100 \:  \times  \: 400} \\

 \Longrightarrow \: \: \sf{K.E \:  =   \: \frac{1}{\cancel2 \: _{1}} \:  \times \: \cancel{100} \: _{50}  \:  \times \: 400} \\

 \Longrightarrow \: \: \sf{K.E \:  =  \:  \frac{1}{1}  \:  \times  \: 50 \:  \times  \: 400} \\

 \Longrightarrow \: \: \sf{K.E \:  =  \: 50 \:  \times  \: 400} \\

 \Longrightarrow \: \: {\textbf{ \textsf{K.E \:  =  \: 20000 \: Joules}}} \\

Hence :-

  • Kinetic Energy = 20000 Joules .

 \rule {180pt}{4pt}

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