Question

if mass of body is 23+0.1 . percentage error is

options
200*10^3
200*10^9
200*10^6
200*10^-6​

Answer 1

Answer:

1.3 %

Explanation:

Given:

• Mass of the body with uncertainty, m plus/minus Delta*m = 23 plus/minus 0.1g .

Velocity of the body with uncertainty, v plus/minus Delta*v = 46 plus/minus 0.2 cm / s .

Therefore,

m = 23 g.

Delta*m = 0.1g .

= 46 cm/s. V =

Av0.2 cm/s.

The Kinetic energy of the body is given by

K.E. = mv².

2

Therefore, the uncertainty in the kinetic energy of the body is given by

AK.E.

K.E.

Am A(v²)

+

m

V

Am m 2Δv V +

0.1 2 × 0.2 + 23 46 0.01304. = (1).

The percentage error in the kinetic energy is given by

Percentage error = Change in K.E./ Original K.E.

Change in K.E. Original K.E. x 100% AK.E. K.E. = x 100%

0.01304 × 100% = 1.304% 1.3%.