Question

if mass of planet is 25 times mass of earth and radius of the planet is 125 times radius of earth the escape velocity of an object from the planet(V p) is_________times the escape velocity from earth(V e).
1) √5
2)1
_____
5
3)5
4) 1
______
√5​

Answer 1

Given:

Mass of the planet = 25 times mass of earth

Radius of planet = 125 times radius of Earth

To find:

Escape velocity of the planet in terms of escape velocity of Earth.

Solution:

As we know that:

Escape Velocity (Ve) = (2GM/ R)^1/2

So for the other planet:

M' = 25M

R' = 125R

Therefore, (Vp) = (2G*25M / 125R)^1/2

Vp = (2GM/ 5R)^1/2 = 1/√5 Ve

Therefore the escape velocity of the planet in terms of escape velocity of the Earth will be 1/√5 Ve.

Answer 2

Answer:

Step-by-step explanation: