Question

If mass of proton =1.008amu and mass of neuteron=1.009amu,then the binding energy performance nucleon for 4be9 (mass=9.012)​

Answer 1

Explanation:

Solution:-

Mass defect,

Δm = (4 × 1.008 + 5 × 1.009) – 9.012

= 9.077 – 9.012 =0.065 amu

BE/A = 0.065 × 931 / 9 = 6.72 MeV

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