If mass of the object is 500 kg find the work done by the object if it is moving with the speed of 72km/h
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By energy conservation laws total work done by the force is equal to the kinetic enery
72km/h =72*1000/3600=20m/s
W = 1/2*mv2=1/2*500*20*20=100000j =100kj
72km/h =72*1000/3600=20m/s
W = 1/2*mv2=1/2*500*20*20=100000j =100kj
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