Science, asked by hydenpaulhyden8177, 11 months ago

If mass og a planet i 8 times of the earth and its radius is twice the radius of the earth, what will be the escape velocity of that planet ?(escape velocity for the earth -11.21cm/s)

Answers

Answered by sbdaule5
0

the escape velocity of that planet will be two times that of Earth because gravitational force is directly proportional to mass and inversely proportional to square of distance so escape velocity of earth planet = escape velocity of Earth x mass of that planet/ mass of x square of radius of planet/ square of radius of earth = escape velocity of earth x 2 = -22.42 cm/ second

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