If maximum weight of lemon is 100g and minimum weight is 40g.What will be the weight of lemon variety with AaBBcc genotype (control by 3 gene)?
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Answered by
2
Answer:
Explanation:
For all dominant AABBCC,,,,wt is 100 gm
So,per allele is 100÷6=16.6
And for all recessive mean minimum wt per allele it will ,,40÷6=6.6
Therefore,for AaBBcc it's wt will be neerly (16.6+6.6+16.6+16.6+6.6+6.6)~=69.6 gm
Answered by
1
Answer:
Weight of Lemon with AaBBcc genotype is approx 70 grams.
Explanation:
Given,
AABBCC= 100g,
aabbcc=40g,
For a heterodominant pair AaBbCc
= (weight of dominant + weight of recessive)/2
=( 100+40 )/2 = 70grams.
Now let us calculate the weight of each gene
In dominant genotype
- Weight of three genes = 100 g
- So weight of each gene = 100/3 = 33.33grams
In recessive genotype
- Weight of three genes = 40 g
- So weight of each gene = 40/3 = 13.33grams
In heterodominant genotype
- weight of three genes = 70grams
- Weight of each gene = 70/3 = 23.33 grams.
Now weight of the genotype AaBBcc is
- weight of Aa = 23.33 g
- Weight of BB = 33.33g
- Weight of cc = 13.33 g
Now adding them = 23.33 + 33.33 + 13.33 = 69.99 grams ~ 70grams.
So the weight of given genotype is 70 grams.
#SP J2
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