Biology, asked by saichandra3319, 11 months ago

If maximum weight of lemon is 100g and minimum weight is 40g.What will be the weight of lemon variety with AaBBcc genotype (control by 3 gene)?

Answers

Answered by duttapratik36
2

Answer:

Explanation:

For all dominant AABBCC,,,,wt is 100 gm

So,per allele is 100÷6=16.6

And for all recessive mean minimum wt per allele it will ,,40÷6=6.6

Therefore,for AaBBcc it's wt will be neerly (16.6+6.6+16.6+16.6+6.6+6.6)~=69.6 gm

Answered by roopini14sl
1

Answer:

Weight of Lemon with AaBBcc genotype is approx 70 grams.

Explanation:

Given,

AABBCC= 100g,

aabbcc=40g,

For a heterodominant pair AaBbCc

= (weight of dominant + weight of recessive)/2

=( 100+40 )/2 = 70grams.

Now let us calculate the weight of each gene

In dominant genotype

  • Weight of three genes = 100 g
  • So weight of each gene = 100/3 = 33.33grams

In recessive genotype

  • Weight of three genes = 40 g
  • So weight of each gene = 40/3 = 13.33grams

In heterodominant genotype

  • weight of three genes = 70grams
  • Weight of each gene = 70/3 = 23.33 grams.

Now weight of the genotype AaBBcc is

  • weight of Aa = 23.33 g
  • Weight of BB = 33.33g
  • Weight of cc = 13.33 g

Now adding them = 23.33 + 33.33 + 13.33 = 69.99 grams ~ 70grams.

So the weight of given genotype is 70 grams.

#SP J2

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