Question

If mean + median = 32 and mean - median = 2, find mode?

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Answer 1

$\huge \boxed{\underbrace{\mathfrak {\underline {\fcolorbox {black}{pink}{Answer}}}}}$

Given:-

__________

___⏬⏬⏬⏬⏬⏬_______

${ mean+median=32 }$

${ mean-median =2 }$

To find:-

____________

_________⏬⏬⏬⏬_____

${ mode=???????? }$

solution:-

___________

_______⏬⏬⏬⏬⏬_____

${ mean+median =32.............(1) }$

${mean-median= 2.................(2) }$

If we solve the equation1 and equation2 ..

we get.... ${ 2\:mean=34 }$

$\implies {mean=\frac{34}{2} }$

$\implies { mean=17 }$

if we put mean's value on equation1

we get... ${ median =32-17 }$

$\implies {median =15 }$

$\boxed{\pink { mode =3\:median-2\:mean } }$

$\implies { mode=(3×15)-(2×17) }$

$\implies {mode=45-34 }$

$\implies\boxed {\red { mode=11} }$✔✔✔✔

Answer 2

Answer:

iven:-

__________

___⏬⏬⏬⏬⏬⏬_______

{ mean+median=32 }mean+median=32

{ mean-median =2 }mean−median=2

To find:-

____________

_________⏬⏬⏬⏬_____

{ mode=???????? }mode=????????

solution:-

___________

_______⏬⏬⏬⏬⏬_____

{ mean+median =32.............(1) }mean+median=32.............(1)

{mean-median= 2.................(2) }mean−median=2.................(2)

If we solve the equation1 and equation2 ..

we get.... { 2\:mean=34 }2mean=34

\implies {mean=\frac{34}{2} }⟹mean=234

\implies { mean=17 }⟹mean=17

if we put mean's value on equation1

we get... { median =32-17 }median=32−17

\implies {median =15 }⟹median=15

\boxed{\pink { mode =3\:median-2\:mean } }mode=3median−2mean

\implies { mode=(3×15)-(2×17) }⟹mode=(3×15)−(2×17)

\implies {mode=45-34 }⟹mode=45−34

\implies\boxed {\red { mode=11} }⟹mode=11 ✔✔✔✔