Question

If mean, mode and variance of a frequency distribution are 43,46 and 81 respectively then find the value of pearson's coefficient of skewness

Answer 1

Answer:

Mean=

x

ˉ

=200,

Coefficient of variation,C.V=8%

Sk

p

=0.3

C.V=

x

ˉ

σ

×100, where σ=standard deviation

∴8=

200

σ

×100

⇒σ=

100

8×200

=16

Now,Sk

p

=

S.D

Mean−Mode

⇒0.3=

16

200−Mode

⇒0.3×16=200−Mode

⇒Mode=200−4.8=195.2

Since,Mean−Mode=3(Mean−Median)

⇒200−195.2=3(200−Median)

⇒4.8=600−3Median

⇒3Median=600−4.8=595.2

∴Median=

3

595.2

=198.4

Explanation:

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