Question

if mean of 4 observations (x + 7), (y - 2), 16 and (3 - z) is 15. then x + y + (-z) =​

Answer 1

Answer:

The marks distribution of 30 students m a mathematics examination are given in Table of Example 1. Find the mode of this data. Also compare and interpret the mode and the mean.

Solution: Solution: Here, Maximum frequency is 7.

So, Modal class will be corresponding class to 7 that is , 40−55.

Now, Mode can be given by formula,

Mode=l+2f1​−f0​−f2​f1​−f0​​∗h

Here, l= Lower limit of modal class =40

f1​= Frequency of Modal class =7

f2​= Frequency of Pre Modal class =3

f3​= Frequency of Succeeding Modal class =6

h= Class interval =15

Putting these values in Mode formula,

Mode=40+14−3−67−3​∗15=40+54​∗15=40+12=52

Mean,(X)=∑fi​∑fi​xi​​=301860​=62

So, Mode=52, indicates maximum students obtained 52 marks.

Mean=62, indicates average marks obtained by student is 62

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