Question

if mean of a,b,c,d,e is 28. Mean of a,c,e is 24
mean of b,d is n^2 -2
find value of N and K
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Answer 1

Answer:

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Step-by-step explanation:

525852856885688239800884223685

Answer 2

Answer:

n = 6

Step-by-step explanation:

If mean of a, b, c, d, and e is 28,

$\frac{a +b+c+d+e}{5} = 28\\a+b+c+d+e = 28 \times 5\\a+b+c+d+e = 140$

If mean of a, c, and e is 24,

$\frac{a+c+e}{3} = 24\\a+c+e = 3 \times 24\\a+c+e = 72$

If mean of b and d is $n^2 - 2$

$\frac{b + d}{2} = n^2 - 2$

Therefore, a + c + e + b + d = 140

                     72 + b + d = 140

                               b + d = 140 - 72

                                b + d = 68

But, $\frac{b+d}{2} = n^2 - 2$

Hence,

     $\frac{68}{2} = n^2 - 2\\34 = n^2 - 2\\n^2 = 34 + 2\\n^2 = 36\\\sqrt{n^2} = \sqrt{36} \\n = 6$