Question

If mean of a given data for a random value is 81.1 and standard deviation is 4.7, then find the probability of getting a value more than 83. ( follow the table for z scores ) 1. 0.44 2. 0.68 3. 0.78 4. 0.34

Answer 1

option (4)

The  probability of getting a value more than 83 = 0.33

Step-by-step explanation:

given  : standard deviation = 4.7

given :  mean value = 81.1

expected value = 83

z score = $\frac{expected - mean}{standard deviation}$

z = $\frac{83-81.1}{4.7}$

z= 0.404255

looking up the z score in the z table , 0.6700.

then probability of getting a value more than 83 = (1- 0.6700)= 0.3333

hence ,

option (4)

The  probability of getting a value more than 83 = 0.34

#Learn more:

The random variable z whose values are these z-scores follows a normal distribution with mean 0 and standard deviation 1, called the standard normal distribution (z n(0,1)). This can be useful when trying to calculate the and of a given normal distribution.

https://brainly.in/question/11328601

Answer 2

Answer:

If mean of a given data for a random value is 81.1 and standard deviation is 4.7, then find the probability of getting a value more than 83.