Question

if mean of geometric distribution is 1 and varience is 2 then the P=
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Answer 1

Answer:

The probability distribution of the number X of Bernoulli trials needed to get one success, supported on the set { 1, 2, 3, ... }

The probability distribution of the number Y = X − 1 of failures before the first success, supported on the set { 0, 1, 2, 3, ... }

Which of these one calls "the" geometric distribution is a matter of convention and convenience.

These two different geometric distributions should not be confused with each other. Often, the name shifted geometric distribution is adopted for the former one (distribution of the number X); however, to avoid ambiguity, it is considered wise to indicate which is intended, by mentioning the support explicitly.

The geometric distribution gives the probability that the first occurrence of success requires k independent trials, each with success probability p. If the probability of success on each trial is p, then the probability that the kth trial (out of k trials) is the first success is

Step-by-step explanation:

Pr(Y=K)