If mean of the following distribution is 24, find the value of a: [4] Marks 0-10 10-20 20-30 30-40 40-50 Number of students 7 a 8 10 5
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Marks Average Marks Number of Students
0−10 5 5
10−20 15 8
20−30 25 15
30−40 53 16
40−50 45 6
Mean =
5+8+15+16+6
5×5+15×8+28×15+35×16+45×6
=
50
1350
=27
So mean deviation about mean =
5+8+15+16+6
5×∣5−27∣+8×∣15−27∣+15×∣25−27∣+16×∣35−27∣+6×∣45−27∣
=
50
472
=9.44
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