if measure of each side of a octagon is 6 centimetre then its perimeter is
please you have to give all answer of MCQ
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ANS 6×8 CM=48CM. IS REQUIRED ANSWER
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Area of the octagon is given as 8 x Area of Triangle.
2 sin²θ = 1- cos 2θ
2 cos²θ = 1+ cos 2θ
tan2θ=1−cos2θ1+cos2θ tan2(452)=1−cos451+cos45 tan2(452)=1−12√1+12√ tan2(452)=2√−12√+1=(2√−1)21 tan(452)=2–√−1 BDOD=2–√−1 OD=a/22√−1=a2(1+2–√)
Area of ∆ AOB = 12×AB×OD
= 12×a×a2(1+2–√)
= a24(1+2–√)
Area of the octagon = 8 x Area of Triangle
Area of Octagon = 8×a24(1+2–√)
Area of an Octagon = 2a2(1+2–√)
2 sin²θ = 1- cos 2θ
2 cos²θ = 1+ cos 2θ
tan2θ=1−cos2θ1+cos2θ tan2(452)=1−cos451+cos45 tan2(452)=1−12√1+12√ tan2(452)=2√−12√+1=(2√−1)21 tan(452)=2–√−1 BDOD=2–√−1 OD=a/22√−1=a2(1+2–√)
Area of ∆ AOB = 12×AB×OD
= 12×a×a2(1+2–√)
= a24(1+2–√)
Area of the octagon = 8 x Area of Triangle
Area of Octagon = 8×a24(1+2–√)
Area of an Octagon = 2a2(1+2–√)
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