Question

If Meena gives an interest of ₹ 450 for one year at 9% p.a., what is the sum she has borrowed?

Answer 1

Step-by-step explanation:

to find the principal we 100*i/t*r

p=100*450/1*9

p=100*50/1

p=500

hope this helps you

mark me as brainliest

Answer 2

Given,

Simple Interest SI = 450rs

Rate Of Interest R = 9%

Time Period T = 1

To Find,

Amount Meena has borrowed

Solution,

Simple Interest SI = 450rs

Interest Rate R = 9%

Period Of Time T = 1

Simple Interest SI = P×R×T

The interest is given in %

SI = $\frac{P*R*T}{100}$

Therefore,

The principal amount =

P =  $\frac{SI*100}{R*T}$

=$\frac{450*100}{1*9}$

=$\frac{45000}{9}$

= 5000rs

5000rs is Meena has borrowed and gives an interest rate of 9%