If meena gives an Interest of Rs. 45 fir one year at 9% rate principal. What is the sum she has borrow.
Answers
Answer:
If Meena gives an interest of ₹45 for one year at 9% rate p.a.. What is the sum she has borrowed?
Solution:
This question can be solved by using the formula of simple interest.
Simple Interest = [Principal × Rate × Time] / 100
Let us assume principal to be P
So, Simple Interest = [Principal × Rate × Time] / 100
The Simple interest, time and rate per annum is given as Rs. 45, 1 years and 9% respectively.
On substituting the values given in the question, we get
⇒ 45 = [P × 9 × 1] / 100
⇒ P = (45 × 100) / 9 × 1
⇒ P = 500
So, Meena borrowed Rs. 500.
Question:
If meena gives an interest of Rs 45 for one year at 9% rate of interest. What is the sum that she has borrowed?
Answer:
Step-by-step explanation:
Given:
Rate of Interest: 9% per annum
Interest: Rs 45
T = 1 year
A = P + 45
Let this be (1)
R% = A-P/P×100
Inserting (1)
9 = P+45-P/P×100
9 = 4500/P
P = 4500/9
P = 500
Meena had borrowed a sum of 500 Rs.