Question

If Meena gives an interest of Rs 45 for one year at 9% rate p.a. what is the sum she has borrowed.

Answer 1

Answer:

The sum borrowed is Rs.500.

Step-by-step explanation:

Given : If Meena gives an interest of Rs.45 for one year at 9% rate p.a.

To find : What is the sum she has borrowed ?

Solution :

Applying interest formula,

$I=P\times R\times T$

Where, I=Rs.45 is the interest

R=9%=0.09 is the interest rate

T=1 year is the time

P is the principal or sum

Substitute the value in the formula,

$45=P\times 0.09\times 1$

$P=\frac{45}{0.09}$

$P=500$

Therefore, The sum borrowed is Rs.500.

Answer 2

Answer:

$\red { sum \: borrowed \:by \:Meena} \green {= Rs \:500 }$

Step-by-step explanation:

$Let \:sum \: borrowed \:by \:Meena = P$

$Rate \:of \: interest (R) = 9\%\:per\:annum$

$Time (T) = 1 \: year$

$Simple \: interest (I) = Rs \:45$

$\boxed {\pink { I = \frac{PTR}{100}}}$

$\implies 45 = \frac{P\times 1 \times 9}{100}$

$\implies \frac{ 45 \times 100}{ 1 \times 9 } = P$

$\implies 500 = P$

Therefore.,

$\red { sum \: borrowed \:by \:Meena} \green {= Rs \:500 }$

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